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KCET · Physics · Rotational Motion

The moment of inertia of a circular ring of radius \(\mathrm{r}\) and mass \(\mathrm{M}\) about diameter is

  1. A \(\frac{2}{5} \mathrm{Mr}^{2}\)
  2. B \(\frac{\mathrm{Mr}^{2}}{4}\)
  3. C \(\frac{\mathrm{Mr}^{2}}{2}\)
  4. D \(\frac{\mathrm{Mr}^{2}}{12}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\mathrm{Mr}^{2}}{2}\)

Step-by-step Solution

Detailed explanation

Moment of inertia of a circular ring about a diameter
\(\mathrm{I}=\frac{1}{2} \mathrm{Mr}^{2}\)