KCET · Physics · Nuclear Physics
\(\beta\)-decay means emission of electron from
- A innermost electron orbit
- B a stable nucleus
- C outermost electron orbit
- D radioactive nucleus
Answer & Solution
Correct Answer
(D) radioactive nucleus
Step-by-step Solution
Detailed explanation
\(\beta\)-emission takes place from a radioactive nucleus as
\({ }_{15}^{32} \mathrm{P} \stackrel{-\beta}{\longrightarrow}{ }_{16}^{32} \mathrm{~S}+{ }_{-1} \mathrm{e}^{0}+\overline{\mathrm{v}}\)
where \(\bar{v}\) is the anti-neutrino.
In \(\beta^{+}\)decay a positron is emitted as
\({ }_{11}^{22} \mathrm{Na} \longrightarrow{ }_{10}^{22} \mathrm{Ne}+{ }_{+1} \mathrm{e}^{0}+\mathrm{v}\)
where \(v\) is the neutrino.
\({ }_{15}^{32} \mathrm{P} \stackrel{-\beta}{\longrightarrow}{ }_{16}^{32} \mathrm{~S}+{ }_{-1} \mathrm{e}^{0}+\overline{\mathrm{v}}\)
where \(\bar{v}\) is the anti-neutrino.
In \(\beta^{+}\)decay a positron is emitted as
\({ }_{11}^{22} \mathrm{Na} \longrightarrow{ }_{10}^{22} \mathrm{Ne}+{ }_{+1} \mathrm{e}^{0}+\mathrm{v}\)
where \(v\) is the neutrino.
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