KCET · Physics · Electromagnetic Induction
An induced current of 2 A flows through a coil. The resistance of the coil is \(10 \Omega\). What is the change in magnetic flux associated with the coil in 1 ms ?
- A \(0.2 \times 10^{-2} \mathrm{~Wb}\)
- B \(2 \times 10^{-2} \mathrm{~Wb}\)
- C \(22 \times 10^{-2} \mathrm{~Wb}\)
- D \(0.22 \times 10^{-2} \mathrm{~Wb}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-2} \mathrm{~Wb}\)
Step-by-step Solution
Detailed explanation
Given, \(I=2 \mathrm{~A}, R=10 \Omega\)
\(t=1 \mathrm{~ms}=10^{-3} \mathrm{~s}\)
We know that,
\(|\varepsilon|=\frac{\Delta \phi}{\Delta t} \Rightarrow I R=\frac{\Delta \phi}{\Delta t}\)
\(\Rightarrow \quad \Delta \phi=I R \Delta t=2 \times 10 \times 10^{-3}\)
\(=0.02 \mathrm{~Wb}=2 \times 10^{-2} \mathrm{~Wb}\)
\(t=1 \mathrm{~ms}=10^{-3} \mathrm{~s}\)
We know that,
\(|\varepsilon|=\frac{\Delta \phi}{\Delta t} \Rightarrow I R=\frac{\Delta \phi}{\Delta t}\)
\(\Rightarrow \quad \Delta \phi=I R \Delta t=2 \times 10 \times 10^{-3}\)
\(=0.02 \mathrm{~Wb}=2 \times 10^{-2} \mathrm{~Wb}\)
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