KCET · Physics · Rotational Motion
A particle is moving uniformly along a straight line as shown in the figure. During the motion of the particle from A to B, the angular momentum of the particle about 'O'
- A remains constant
- B increases
- C first increases then decreases
- D decreases
Answer & Solution
Correct Answer
(A) remains constant
Step-by-step Solution
Detailed explanation
Angular momentum L=mvr
where r is the perpendicular distance between velocity and reference point
Here since the line AB is straight, there would only 1 perpendicular distance from reference point i.e OA
So,
Angular momentum at A =mvr
Angular momentum at P =mvr
Angular momentum at B =mvr
Since, perpendicular distance between the line AB and O will always be R
So all the points lying on the line AB will have same angular momentum equals to mvr.
where r is the perpendicular distance between velocity and reference point
Here since the line AB is straight, there would only 1 perpendicular distance from reference point i.e OA
So,
Angular momentum at A =mvr
Angular momentum at P =mvr
Angular momentum at B =mvr
Since, perpendicular distance between the line AB and O will always be R
So all the points lying on the line AB will have same angular momentum equals to mvr.
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