KCET · Physics · Atomic Physics
The total energy of an electron revolving in the second orbit of hydrogen atom is
- A \(-13.6 \mathrm{ev} \)
- B \( -1.51 \mathrm{ev} \)
- C \( -3.4 \mathrm{ev} \)
- D Zero
Answer & Solution
Correct Answer
(C) \( -3.4 \mathrm{ev} \)
Step-by-step Solution
Detailed explanation
Total energy of an electron revolving in nth orbit of hydrogen atom is given as
\( E_{n}=\frac{-13.6}{n^{2}} \mathrm{eV} \)
For second orbit, \( n=2 \), energy is
\( E_{2}=\frac{-13.6}{2^{2}}=-3.4 e V \)
\( E_{n}=\frac{-13.6}{n^{2}} \mathrm{eV} \)
For second orbit, \( n=2 \), energy is
\( E_{2}=\frac{-13.6}{2^{2}}=-3.4 e V \)
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