KCET · Physics · Mechanical Properties of Fluids
A cylindrical container containing water has a small hole at height of \( \mathrm{H}=8 \mathrm{~cm} \) from the bottom and at a depth of \( 2 \mathrm{~cm} \) from the top surface of the liquid. The maximum horizontal distance travelled by the water before it hits the ground \( (x) \) is
- A \( 4 \mathrm{~cm} \)
- B \( 8 \mathrm{~cm} \)
- C \( 6 \mathrm{~cm} \)
- D \( 4 \sqrt{2} \mathrm{~cm} \)
Answer & Solution
Correct Answer
(B) \( 8 \mathrm{~cm} \)
Step-by-step Solution
Detailed explanation
(B)
\(v=\sqrt{2 g h}=\sqrt{2 \times 10 \times 2}=\sqrt{40} \)
\(t=\sqrt{\frac{2 h}{g}} \)
\(R=v \cdot t=\sqrt{40^{4}} \sqrt{\frac{2 \times 8}{10}}=8 \mathrm{~cm}\)
\(v=\sqrt{2 g h}=\sqrt{2 \times 10 \times 2}=\sqrt{40} \)
\(t=\sqrt{\frac{2 h}{g}} \)
\(R=v \cdot t=\sqrt{40^{4}} \sqrt{\frac{2 \times 8}{10}}=8 \mathrm{~cm}\)
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