KCET · Maths · Functions
If the function is \(f(x)=\frac{1}{x+2}\), then the point of discontinuity of the composite function \(y=f(f(x))\) is
- A \(\frac{5}{2}\)
- B \(\frac{2}{5}\)
- C \(\frac{1}{2}\)
- D \(\frac{-5}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{-5}{2}\)
Step-by-step Solution
Detailed explanation
\(y=f(f(x))=f\left(\frac{1}{2+x}\right)\)
\(=\frac{1}{2+\frac{1}{2+x}}=\frac{2+x}{4+2 x+1}=\frac{2+x}{5+2 x}\)
This function is not continuous at \(x=-2\) (because \(f(x)\) is not defined at this point) and \(x=-\frac{5}{2}\) because \(f(f(x))\) is not defined at this point.
\(=\frac{1}{2+\frac{1}{2+x}}=\frac{2+x}{4+2 x+1}=\frac{2+x}{5+2 x}\)
This function is not continuous at \(x=-2\) (because \(f(x)\) is not defined at this point) and \(x=-\frac{5}{2}\) because \(f(f(x))\) is not defined at this point.
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