KCET · Chemistry · Chemical Kinetics
The rate constant of a reaction is given by \(k=P Z e^{-E_{a} / R T}\) under standard notation. In order to speed up the reaction, which of the following factors has to be decreased?
- A \(Z\)
- B Both \(Z\) and \(T\)
- C \(E_{a}\)
- D \(T\)
Answer & Solution
Correct Answer
(C) \(E_{a}\)
Step-by-step Solution
Detailed explanation
\(\therefore k=P Z e^{-E a / R T}\)
The above reaction expression is given in terms of exponents. We have to increase the speed of reaction. So, value of \(k\) has to be more and as per the given expression.
\(k \propto \frac{1}{e^{E_{a} / R T}}\)
if \(E a\) decreases, than \(\left[e^{E_{a} / R T}\right]\) also decreases and \(\left[e^{\frac{1}{E_{a} / R T}}\right]\) increases.
\(\therefore k\) also increases
The above reaction expression is given in terms of exponents. We have to increase the speed of reaction. So, value of \(k\) has to be more and as per the given expression.
\(k \propto \frac{1}{e^{E_{a} / R T}}\)
if \(E a\) decreases, than \(\left[e^{E_{a} / R T}\right]\) also decreases and \(\left[e^{\frac{1}{E_{a} / R T}}\right]\) increases.
\(\therefore k\) also increases
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