KCET · Physics · Dual Nature of Matter
The photoelectric work function for photo metal is 2.4 eV . Among the four wavelengths, the wavelength of light for which photoemission does not take place is
- A 200 nm
- B 300 nm
- C 700 nm
- D 400 nm
Answer & Solution
Correct Answer
(C) 700 nm
Step-by-step Solution
Detailed explanation
Given, \(\phi_0=24 \mathrm{eV}\)
We know that, \(\phi_0=\frac{1240}{\lambda_0(\text { in } \mathrm{nm})}\)
\(\Rightarrow \quad \lambda_0(\) in nm\()=\frac{1240}{\phi_0}=\frac{1240}{24}=516.6 \mathrm{~nm}\)
We know that, \(\phi_0=\frac{1240}{\lambda_0(\text { in } \mathrm{nm})}\)
\(\Rightarrow \quad \lambda_0(\) in nm\()=\frac{1240}{\phi_0}=\frac{1240}{24}=516.6 \mathrm{~nm}\)
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