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Vapour pressure of pure 'A' is \(70 \mathrm{~mm}\) of \(\mathrm{Hg}\) at \(25^{\circ} \mathrm{C}\). It forms an ideal solution with ' \(B\) ' in which mole fraction of \(A\) is \(0.8\). If the vapour pressure of the solution is \(84 \mathrm{~mm}\) of \(\mathrm{Hg}\) at \(25^{\circ} \mathrm{C}\), the vapour pressure of pure ' \(B\) ' at \(25^{\circ} \mathrm{C}\) is
- A \(28 \mathrm{~mm}\)
- B \(56 \mathrm{~mm}\)
- C \(70 \mathrm{~mm}\)
- D \(140 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(D) \(140 \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{p}=\mathrm{p}_{\mathrm{A}}^{\circ} \mathrm{x}_{\mathrm{A}}+\mathrm{p}_{\mathrm{B}}^{\circ} \mathrm{x}_{\mathrm{B}}\)
\(\Rightarrow \quad 84=70 \times 0.8+\mathrm{p}_{\mathrm{B}}^{\circ} \times 0.2\)
\(84=56+\mathrm{p}_{\mathrm{B}}^{\circ} \times 0.2\)
\(\mathrm{p}_{\mathrm{B}}^{\circ}=\frac{28}{0.2}=140 \mathrm{~mm}\)
\(\Rightarrow \quad 84=70 \times 0.8+\mathrm{p}_{\mathrm{B}}^{\circ} \times 0.2\)
\(84=56+\mathrm{p}_{\mathrm{B}}^{\circ} \times 0.2\)
\(\mathrm{p}_{\mathrm{B}}^{\circ}=\frac{28}{0.2}=140 \mathrm{~mm}\)
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