KCET · Chemistry · Electrochemistry
Addition of excess of \( \mathrm{AgNO}_{3} \) to an aqueous solution of \( 1 \) mole of \( \mathrm{PdCl}_{2} \cdot 4 \mathrm{NH}_{3} \) gives \( 2 \)
moles of \( \mathrm{AgCl} \). The conductivity of this solution corresponds to
- A \( 1: 2 \) electrolyte
- B \( 1: 4 \) electrolyte
- C \( 1: 1 \) electrolyte
- D \( 1: 3 \) electrolyte
Answer & Solution
Correct Answer
(A) \( 1: 2 \) electrolyte
Step-by-step Solution
Detailed explanation
(A)
\( \left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2} \rightarrow\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}+2 \mathrm{Cl}^{-} \)
It is \( 1: 2 \mathrm{i} . \mathrm{e}, A B_{2} \) type of electrolyte.
\( \left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2} \rightarrow\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}+2 \mathrm{Cl}^{-} \)
It is \( 1: 2 \mathrm{i} . \mathrm{e}, A B_{2} \) type of electrolyte.
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