KCET · Chemistry · Chemical Bonding and Molecular Structure
Which one of the following has no unpaired electrons?
- A \(\mathrm{O}_{2}^{-}\)
- B \(\mathrm{O}_{2}^{+}\)
- C \(\mathrm{O}_{2}^{2-}\)
- D \(\mathrm{O}_{2}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{O}_{2}^{2-}\)
Step-by-step Solution
Detailed explanation
(a) In \(\mathrm{O}_{2}^{-}\)total number of electrons
\[
=16+1=17
\]
\(\therefore\) Orbital arrangement
\[
\begin{aligned}
=K K^{\prime}, \sigma 2 s^{2}, \sigma 2 s^{2}, \sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}, \\
\pi 2 p_{x}^{2} &=\pi 2 p_{y}^{1}
\end{aligned}
\]
(b) In \(\mathrm{O}_{2}^{+}\), total number of electrons
\[
=16-1=15
\]
\(\therefore\) Orbital arrangement \(=\mathrm{KK}^{\prime}, \sigma 2 \mathrm{~s}^{2}, \sigma 2 \mathrm{~s}^{2}\),
\[
\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}, \stackrel{\approx}{\pi} 2 \mathrm{p}_{\mathrm{x}}^{1}
\]
(c) In \(\mathrm{O}_{2}^{2-}\), total number of electrons
\[
=16+2=18
\]
\(\therefore\) Orbital arrangement \(=K_{K}^{\prime}, \sigma 2 \mathrm{~s}^{2}, \sigma 2 \mathrm{~s}^{2}\), \(\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}\)
(d) In \(\mathrm{O}_{2}\), total number of electrons \(=16\)
\(\therefore\) Orbital arrangement \(=K K K^{\prime}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}\),
\(\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \pi 2 \mathrm{p}_{\mathrm{y}}^{2}, \stackrel{\approx}{\pi} 2 \mathrm{p}_{\mathrm{x}}^{1} \approx \pi / 2 \mathrm{p}_{\mathrm{y}}^{1}\)
Hence, only \(\mathrm{O}_{2}^{2-}\) has no unpaired electrons.
\[
=16+1=17
\]
\(\therefore\) Orbital arrangement
\[
\begin{aligned}
=K K^{\prime}, \sigma 2 s^{2}, \sigma 2 s^{2}, \sigma 2 p_{z}^{2}, \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}, \\
\pi 2 p_{x}^{2} &=\pi 2 p_{y}^{1}
\end{aligned}
\]
(b) In \(\mathrm{O}_{2}^{+}\), total number of electrons
\[
=16-1=15
\]
\(\therefore\) Orbital arrangement \(=\mathrm{KK}^{\prime}, \sigma 2 \mathrm{~s}^{2}, \sigma 2 \mathrm{~s}^{2}\),
\[
\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}, \stackrel{\approx}{\pi} 2 \mathrm{p}_{\mathrm{x}}^{1}
\]
(c) In \(\mathrm{O}_{2}^{2-}\), total number of electrons
\[
=16+2=18
\]
\(\therefore\) Orbital arrangement \(=K_{K}^{\prime}, \sigma 2 \mathrm{~s}^{2}, \sigma 2 \mathrm{~s}^{2}\), \(\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}\)
(d) In \(\mathrm{O}_{2}\), total number of electrons \(=16\)
\(\therefore\) Orbital arrangement \(=K K K^{\prime}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}\),
\(\sigma 2 \mathrm{p}_{\mathrm{z}}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \pi 2 \mathrm{p}_{\mathrm{y}}^{2}, \stackrel{\approx}{\pi} 2 \mathrm{p}_{\mathrm{x}}^{1} \approx \pi / 2 \mathrm{p}_{\mathrm{y}}^{1}\)
Hence, only \(\mathrm{O}_{2}^{2-}\) has no unpaired electrons.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Dialysis can be used to separateKCET 2012 Medium
- Which of the following is least soluble in water at \( 298 \mathrm{~K} ? \)KCET 2019 Medium
- The glycosidic linkage involved in linking the glucose units in amylose part of starch isKCET 2018 Easy
- -propyl bromide on treating with alcoholic \(\mathrm{KOH}\) producesKCET 2008 Medium
- Solubility of \( \mathrm{AgCl} \) is least inKCET 2019 Medium
- Acetic acid is treated with \( \mathrm{Ca}(\mathrm{OH})_{2} \) and the product so obtained is subjected to dry
distillation. The final product isKCET 2015 Easy
More PYQs from KCET
- The value of \(\cot ^{-1}\left[\frac{\sqrt{1-\sin x}+\sqrt{1+\sin x}}{\sqrt{1-\sin x}-\sqrt{1+\sin x}}\right]\), where \(x \in\left(0, \frac{\pi}{4}\right)\) isKCET 2023 Hard
- Identify the floral unit 'T' in the given floral diagram.
KCET 2020 Easy - Some of the steps of DNA fingerprinting are given below. Identify the correct sequence from the options given.
A. Electrophoresis of DNA fragments
B. Hybridsation with DNA probe
C. Digestion of DNA by RENS
D. Autoradiography
E Blotting of DNA fragments to nitrocellulose membraneKCET 2014 Medium - If \( P, Q \) and \( R \) are physical quantities having different dimensions, which of the following
combinations can never be a meaningful quantity?KCET 2019 Easy - One mole of \( 4 \) gas is heated at constant pressure starting at \( 27{ }^{\circ} \mathrm{C} . \) How much energy must be added to the gas as heat to double its volume?KCET 2019 Medium
- The displacement \(x\) (in \(\mathrm{m})\) of a particle of mass \(m\) (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time \(t\) (in sec) by \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will beKCET 2022 Hard