KCET · Chemistry · Chemical Equilibrium
The equilibrium constant at 298 K for the reaction \(\mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}\) is 100 . If the initial concentrations of all the four species were 1 M each, then equilibrium concentration of \(D\) (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) will be
- A \(0.182\)
- B \(1.818\)
- C \(1.182\)
- D \(0.818\)
Answer & Solution
Correct Answer
(B) \(1.818\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned}
& 100=\frac{(1+x)(1+x)}{(1-x)(1-x)} \\
& \Rightarrow \quad \frac{1+x}{1-x}=10 \\
& \Rightarrow \quad 1+x=10-10 x \\
& \Rightarrow \quad 11 x=9 \\
& x=\frac{9}{11}=0.818
\end{aligned}\)
(D) \(1+x=1+0.818=1.818\)
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