KCET · Chemistry · General Organic Chemistry
Arrange benzene, \(n\)-hexane and ethyne in decreasing order of their acidic behaviour.
- A Benzene \(>n\)-hexane \(>\) Ethyne
- B \(n\)-hexane \(>\) Benzene \(>\) Ethyne
- C Ethyne \(>n\)-hexane \(>\) Benzene
- D Ethyne \(>\) Benzene \(>n\)-hexane
Answer & Solution
Correct Answer
(D) Ethyne \(>\) Benzene \(>n\)-hexane
Step-by-step Solution
Detailed explanation
The decreasing order of acidic behaviour is ethyne \(>\) benzene \(>n\)-hexane
Because carbon in ethyne, benzene and \(n\)-hexane are \(s p, s p^{2}\) and \(s p^{3}\) hybridised respectively.
\(\therefore\) The carbocation formed after the removal of ' \(\mathrm{H}\) ' is more stable in \(s p\) hybridised carbon atom because of high electronegativity due to more \(s\)-character.
Because carbon in ethyne, benzene and \(n\)-hexane are \(s p, s p^{2}\) and \(s p^{3}\) hybridised respectively.
\(\therefore\) The carbocation formed after the removal of ' \(\mathrm{H}\) ' is more stable in \(s p\) hybridised carbon atom because of high electronegativity due to more \(s\)-character.
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