KCET · Physics · Magnetic Effects of Current
If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is
- A \( T=\frac{1}{2 \Pi} \sqrt{\frac{M B}{I}} \)
- B \( T=\frac{1}{2 \Pi} \sqrt{\frac{I}{M B}} \)
- C \( T=2 \Pi \sqrt{\frac{I}{M B}} \)
- D \( T=2 \Pi \sqrt{\frac{M B}{I}} \)
Answer & Solution
Correct Answer
(C) \( T=2 \Pi \sqrt{\frac{I}{M B}} \)
Step-by-step Solution
Detailed explanation
If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is
\(T=2 \pi \sqrt{\frac{I}{M B}}\)
\(T=2 \pi \sqrt{\frac{I}{M B}}\)
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