ExamBro
ExamBro
KCET · Chemistry · Structure of Atom

Two particles \(A\) and \(B\) are in motion. If the wavelength associated with particle \(A\) is \(5 \times 10^{-8} \mathrm{~m}\). Calculated the wavelength (in Ã…) associated with particle B if its momentum is half of \(\mathrm{A}\).

  1. A \( 1.25 \times 10^{-7} \mathrm{~m} \)
  2. B \( 1.0 \times 10^{-7} \mathrm{~m} \)
  3. C \( 1.0 \times 10^{-8} \mathrm{~m} \)
  4. D \( 2.5 \times 10^{-8} \mathrm{~m} \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 1.0 \times 10^{-7} \mathrm{~m} \)

Step-by-step Solution

Detailed explanation

By de Broglie equation, \(\lambda_{A}=h / P_{A}\)
And \(\lambda_{B}=h / P_{B}\)
\(\lambda_{A} / \lambda_{B}=P_{A} / P_{B}\)
\(P_{B}=1 / 2 P_{A}(\) Given \()\)
\(\lambda_{A} / \lambda_{B}=1 / 2 P_{A} / P_{A}=P_{A}\)
\(\lambda_{B}=2 \lambda_{A}\)
\(\lambda_{B}=2 \times 5 \times 10^{-8} \mathrm{~m}\)
\(=10^{-7} \mathrm{~m}\)