KCET · Chemistry · Coordination Compounds
The correct set of quantum number for the unpaired electrons of chlorine atom is
- A \( 2,0,0,+\frac{1}{2} \)
- B \( 2,1,-1,+\frac{1}{2} \)
- C \( 3,1,1, \pm \frac{1}{2} \)
- D \( 3,0,0, \pm \frac{1}{2} \)
Answer & Solution
Correct Answer
(C) \( 3,1,1, \pm \frac{1}{2} \)
Step-by-step Solution
Detailed explanation
Electronic configuration for C l(Z=17) is \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}\)
\(\begin{array}{|c|c|c|c|} \hline m_{1} & -1 & 0 & -1 \\ \hline 3 p^{5} & 1 l & 1 l & 1 \\ \hline \end{array}\)
The values of quantum number for the above configuration is
\(\begin{array}{|c|c|c|c|} \hline \mathrm{n} & \mathrm{I} & m_{1} & m_{s} \\ \hline 3 & 1 & 1 & \pm \frac{1}{2} \\ \hline \end{array}\)
\(\begin{array}{|c|c|c|c|} \hline m_{1} & -1 & 0 & -1 \\ \hline 3 p^{5} & 1 l & 1 l & 1 \\ \hline \end{array}\)
The values of quantum number for the above configuration is
\(\begin{array}{|c|c|c|c|} \hline \mathrm{n} & \mathrm{I} & m_{1} & m_{s} \\ \hline 3 & 1 & 1 & \pm \frac{1}{2} \\ \hline \end{array}\)
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