KCET · Chemistry · Aldehydes and Ketones
An organic compound \(X\) on treatment with PCC in dichloromethane gives the compound \(Y\). Compound \(Y\) reacts with \(\mathrm{I}_{2}\) and alkali to form yellow precipitate of triiodomethane. The compound \(X\) is
- A \(\mathrm{CH}_{3} \mathrm{CHO}\)
- B \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
- C \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
- D \(\mathrm{CH}_{3} \mathrm{COOH}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
Step-by-step Solution
Detailed explanation
Compound \((Y)\) gives iodoform test, that means it contains acetyl group

PCC is an oxidising agent which oxidised the alcohol to aldehyde or ketone (depends upon the reactant alcohol). That means \(X\) is an alcohol.
From the given information, it is concluded that the compound \(X\) is an alcohol (which contain two carbon). Thus, the alcohol is \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\).
The reaction involves are as follows:


PCC is an oxidising agent which oxidised the alcohol to aldehyde or ketone (depends upon the reactant alcohol). That means \(X\) is an alcohol.
From the given information, it is concluded that the compound \(X\) is an alcohol (which contain two carbon). Thus, the alcohol is \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\).
The reaction involves are as follows:

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