KCET · Chemistry · Thermodynamics (C)
The process is spontaneous at the given temperature, if
- A \(\Delta H\) is +ve and \(\Delta S\) is -ve
- B \(\Delta H\) is -ve and \(\Delta S\) is +ve
- C \(\Delta H\) is +ve and \(\Delta S\) is +ve
- D \(\Delta H\) is +ve and \(\Delta S\) is equal to zero
Answer & Solution
Correct Answer
(B) \(\Delta H\) is -ve and \(\Delta S\) is +ve
Step-by-step Solution
Detailed explanation
According to Gibbs' energy equation
\(\Delta G=\Delta H-T \Delta S\)
when \(\Delta H\) is negatie but \(T \Delta S\) is positive, i.e., energy factor as well as the randomness factor favour the process. The process will be highly spontaneous and \(\Delta G\) will be highly negative.
\(\Delta G=\Delta H-T \Delta S\)
when \(\Delta H\) is negatie but \(T \Delta S\) is positive, i.e., energy factor as well as the randomness factor favour the process. The process will be highly spontaneous and \(\Delta G\) will be highly negative.
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