KCET · Chemistry · Coordination Compounds
The coordination number of \(F e\) and \(C o\) in the complex ions, \(\left.\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\) and \(\left[\mathrm{Co}(\mathrm{SCN})_{4}\right]^{2-}\) are respectively
- A 3 and 4
- B 6 and 8
- C 4 and 6
- D 6 and 4
Answer & Solution
Correct Answer
(D) 6 and 4
Step-by-step Solution
Detailed explanation
The coordination number of \(\mathrm{Fe}\) in \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3+}\) is 6 and Co in \(\left[\mathrm{Co}(\mathrm{SCN})_{4}\right]^{2-}\) is 4 . It is because \(\mathrm{C}_{2} \mathrm{O}_{4}\) is a bidentate ligand. So, \(3 \times 2=6\)
SCN is a monodendate ligand \(4 \times 1=4\)
So, depending upon the number of the ligands, we can calculate the coordination number of central metal atom.
SCN is a monodendate ligand \(4 \times 1=4\)
So, depending upon the number of the ligands, we can calculate the coordination number of central metal atom.
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