KCET · Chemistry · Electrochemistry
The pair of electrolytes that posses same value for the constant \((A)\) in the Debye-Huckel-Onsager equation, \(\Lambda_{m}=\Lambda_{m}^{\circ}-A \sqrt{C}\) is
- A \(\mathrm{MgSO}_{4}, \mathrm{NaSO}_{4}\)
- B \(\mathrm{NH}_{4} \mathrm{Cl}, \mathrm{NaBr}\)
- C \(\mathrm{NaBr}, \mathrm{MgSO}_{4}\)
- D \(\mathrm{NaCl}, \mathrm{CaCl}_{2}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{NH}_{4} \mathrm{Cl}, \mathrm{NaBr}\)
Step-by-step Solution
Detailed explanation
\(\Lambda_{m}=\Lambda_{m}^{\circ}-A \sqrt{C}\)
Out of all the given pairs, the pair having same (similar) charges will possess the same value of \(A\). Here, \(\mathrm{MgSO}_{4}\) and \(\mathrm{Na}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Mg}^{2+}\) and \(\mathrm{Na}^{+}\)
\(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{NaBr} \rightarrow \mathrm{NH}_{4}^{+}\)and \(\mathrm{Na}^{+}\)
\(\mathrm{NaBr}\) and \(\mathrm{MgSO}_{4} \rightarrow \mathrm{Na}^{+}\)and \(\mathrm{Mg}^{2+}\)
\(\mathrm{NaCl}\) and \(\mathrm{CaCl}_{2} \rightarrow \mathrm{Na}^{+}\)and \(\mathrm{Ca}^{2+}\)
So, only in \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{NaBr}\), the charge is same on both the cations and hence, there will have same value of \(A\).
Out of all the given pairs, the pair having same (similar) charges will possess the same value of \(A\). Here, \(\mathrm{MgSO}_{4}\) and \(\mathrm{Na}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Mg}^{2+}\) and \(\mathrm{Na}^{+}\)
\(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{NaBr} \rightarrow \mathrm{NH}_{4}^{+}\)and \(\mathrm{Na}^{+}\)
\(\mathrm{NaBr}\) and \(\mathrm{MgSO}_{4} \rightarrow \mathrm{Na}^{+}\)and \(\mathrm{Mg}^{2+}\)
\(\mathrm{NaCl}\) and \(\mathrm{CaCl}_{2} \rightarrow \mathrm{Na}^{+}\)and \(\mathrm{Ca}^{2+}\)
So, only in \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(\mathrm{NaBr}\), the charge is same on both the cations and hence, there will have same value of \(A\).
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