KCET · Chemistry · Chemical Equilibrium

For the reaction, \(A(g)+B(g) \rightleftharpoons C(g)+D(g) ; \Delta H=Q \mathrm{~kJ}\)
The equilibrium constant cannot be disturbed by

A addition of \(A\)
B addition of \(D\)
C increasing of pressure
D increasing of temperature

Verified Solution

Answer & Solution

Correct Answer

(C) increasing of pressure

Step-by-step Solution

Detailed explanation

For the given hypothetical reaction,
\(A(g)+B(g) \rightleftharpoons C(g)+D(g) ; \Delta H=-Q \mathrm{~kJ}\)
\(\Delta n=0\), because number of molecules of gaseous molecule on both side are equal. Thus, the equilibrium constant cannot be disturbed by increasing of pressure.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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For the reaction, \(A(g)+B(g) \rightleftharpoons C(g)+D(g) ; \Delta H=Q \mathrm{~kJ}\)The equilibrium constant cannot be disturbed by

Step-by-step Solution

For the reaction, \(A(g)+B(g) \rightleftharpoons C(g)+D(g) ; \Delta H=Q \mathrm{~kJ}\)
The equilibrium constant cannot be disturbed by