KCET · Chemistry · Electrochemistry
\(100 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) acetic acid is completely neutralized using a standard solution of \(\mathrm{NaOH}\). The volume of ethane obtained at STP after the complete electrolysis of the resulting solution is
- A \(56 \mathrm{~mL}\).
- B \(224 \mathrm{~mL}\)
- C \(560 \mathrm{~mL}\)
- D \(112 \mathrm{~mL}\).
Answer & Solution
Correct Answer
(D) \(112 \mathrm{~mL}\).
Step-by-step Solution
Detailed explanation
Acetic acid on electrolysis gives ethane as
Given moles of acetic acid,
\[
\mathrm{CH}_{3} \mathrm{COOH}=\frac{0.1 \times 100}{1000}=0.01
\]
\(\because 2 \mathrm{~mol} \mathrm{CH}_{3} \mathrm{COOH}\) gives \(\mathrm{C}_{2} \mathrm{H}_{6}=22.4 \mathrm{~L}\)
\(\therefore 0.01 \mathrm{~mol} \mathrm{CH} \mathrm{CHOH}_{3} \mathrm{COOH}\) give
\[
\begin{aligned}
\mathrm{C}_{2} \mathrm{H}_{6} &=\frac{22.4 \times 0.01}{2} \\
&=0.112 \mathrm{~L} \\
&=112 \mathrm{~mL}
\end{aligned}
\]
Given moles of acetic acid,
\[
\mathrm{CH}_{3} \mathrm{COOH}=\frac{0.1 \times 100}{1000}=0.01
\]
\(\because 2 \mathrm{~mol} \mathrm{CH}_{3} \mathrm{COOH}\) gives \(\mathrm{C}_{2} \mathrm{H}_{6}=22.4 \mathrm{~L}\)
\(\therefore 0.01 \mathrm{~mol} \mathrm{CH} \mathrm{CHOH}_{3} \mathrm{COOH}\) give
\[
\begin{aligned}
\mathrm{C}_{2} \mathrm{H}_{6} &=\frac{22.4 \times 0.01}{2} \\
&=0.112 \mathrm{~L} \\
&=112 \mathrm{~mL}
\end{aligned}
\]
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