KCET · Maths · Limits
In a class of \( 60 \) students, \( 25 \) students play cricket and \( 20 \) students play tennis, and \( 10 \) students
play both the games, then the number of students who play neither is
- A \( 00 \)
- B \( 35 \)
- C \( 15 \)
- D (25)
Answer & Solution
Correct Answer
(D) (25)
Step-by-step Solution
Detailed explanation
Given that \(n=60, n(C)=25, n(T)=20\) and \(n(C \cap T)=10\)
Now,
\(n(C \cup T)=n(C)+n(T)-n(C \cap T)\)
\(=25+20-10=35\)
Therefore, \(n(C \cap T)=n-n(C \cup T)\)
\(=60-35=25\)
Now,
\(n(C \cup T)=n(C)+n(T)-n(C \cap T)\)
\(=25+20-10=35\)
Therefore, \(n(C \cap T)=n-n(C \cup T)\)
\(=60-35=25\)
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