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JEE Mains · Maths · STD 11 - 12. limits

For each \(t \in R\) ,let \(\left[ t \right]\) be the greatest interger less than or equal to \(t\) . Then \(\mathop {\lim }\limits_{x \to 0 + } x\left( {\left[ {\frac{1}{x}} \right] + \left[ {\frac{2}{x}} \right] + .\;.\;.\; + \left[ {\frac{{15}}{x}} \right]} \right) =\) . .. . .

  1. A \(15\)
  2. B \(120\)
  3. C does not exit (In \(R\))
  4. D \(0\)
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Answer & Solution

Correct Answer

(B) \(120\)

Step-by-step Solution

Detailed explanation

\((2)\) Since, \(\mathop {\lim }\limits_{x \to {0^ + }} x\left( {\left[ {\frac{1}{x}} \right] + \left[ {\frac{2}{x}} \right] + .... + \left[ {\frac{{15}}{x}} \right]} \right)\)…
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