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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2020
- Medium
- Numerical
The surface of a metal is illuminated altemately with photons of energies \(E _{1}=4\, eV\) and \(E _{2}=2.5\, eV\) respectively. The ratio of maximum speeds of the photoelectrons emitted in the two cases is \(2 .\) The work function of the metal in \(( eV )\) is\(......ev\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(E _{1}=\phi+ K _{1} \ldots(1)\)
\(E _{2}=\phi+ K _{2}\) \(...(2)\)
\(E _{1}- E _{2}= K _{1}- K _{2}\)
Now \(\frac{ V _{1}}{ V _{2}}=2\)
\(\frac{ K _{1}}{ K _{2}}=4\)
\(K _{1}=4 K _{2}\)
Now from equation \((2)\)
\(\Rightarrow 4-2.5=4 K _{2}- K _{2}\)
\(1.5=3 K _{2}\)
\(K _{2}=0.5 eV\)
Now putting This
Value in equation \(( 2 )\)
\(2.5=\phi+0.5 eV\)
\(\phi=2 ev\)
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