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JEE Mains · Maths · STD 11 - 7. binomial theoram

The term independent of ' \(x\) ' in the expansion of \(\left(\frac{x+1}{x^{2 / 3}-x^{1 / 3}+1}-\frac{x-1}{x-x^{1 / 2}}\right)^{10}\), where \(x \neq 0,1\) is equal to \(.....\)

  1. A \(110\)
  2. B \(210\)
  3. C \(300\)
  4. D \(400\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(210\)

Step-by-step Solution

Detailed explanation

\(\left(\left(x^{1 / 3}+1\right)-\left(\frac{x^{1 / 2}+1}{x^{1 / 2}}\right)\right)^{10}\) \(=\left(x^{1 / 3} \frac{1}{x^{1 / 2}}\right)^{10}\) Now General Term…
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