JEE Mains · Physics · STD 12 - 3. current electricity
What will be the most suitable combination of three resistors \(A =2\, \Omega, B =4\, \Omega, C =6\, \Omega\) so that \(\left(\frac{22}{3}\right)\Omega\) is equivalent resistance of combination\(?\)
- A Parallel combination of \(A\) and \(C\) connected in series with \(B\)
- B Parallel combination of \(A\) and \(B\) connected in series with \(C\).
- C Series combination of \(A\) and \(C\) connected in parallel with \(B\).
- D Series combination of \(B\) and \(C\) connected in parallel with \(A\).
Answer & Solution
Correct Answer
(B) Parallel combination of \(A\) and \(B\) connected in series with \(C\).
Step-by-step Solution
Detailed explanation
\(\Rightarrow \frac{4}{3}+6=\frac{22}{3}\)
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