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JEE Mains · Physics · STD 11 - 13. oscillations
Two simple pendulums of length \(1\, m\) and \(4\, m\) respectively are both given small displacement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed number of oscillations equal to
- A \(2\)
- B \(7\)
- C \(5\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Let \(\mathrm{T}_{1}\) and \(\mathrm{T}_{2}\) be the time period of the two pendulums \(T_{1}=2 \pi \sqrt{\frac{1}{g}}\) and \(T_{2}=2 \pi \sqrt{\frac{4}{g}}\) As \(\ell_{1}<\ell_{2}\) therefore \(\mathrm{T}_{1}<\mathrm{T}_{2}\) Let at \(t=0\) they start swinging together. since…
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