JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2019
- Hard
- MCQ
Two particles are projected from the same point with the same speed \(u\) such that they have the same range \(R\), but different maximum heights, \(h_1\) and \(h_2\). Which of the following is correct ?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(R^2 = 16 h_1h_2\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l} For\,same\,range\,angle\,of\,projection\,will\\ be\,\theta \,will\,be\,\theta \,\& \,90 - \theta \\ R\,\, = \,\frac{{{u^2}2\sin \theta \cos \theta }}{g}\\ {h_1} = \frac{{{u^2}{{\sin }^2}\theta }}{g}\\ {h_2} = \frac{{{u^2}\sin {\,^2}\left( {90 - \theta } \right)}}{g}\\ \frac{{{R^2}}}{{{h_1}{h_2}}} = 16 \end{array}\)


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