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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2022
  • Medium
  • MCQ

When a particle executes simple Harmonic motion, the nature of graph of velocity as function of displacement will be.

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Answer & Solution

Correct Answer

(B) Ellipitical

Step-by-step Solution

Detailed explanation

For a particle in SHM, its speed depends on position as

\(v=\omega \sqrt{A^{2}-x^{2}}\)

Where \(\omega\) is angular frequency and \(A\) is amplitude Now \(v ^{2}=\omega^{2} A ^{2}-\omega^{2} x ^{2}\)

So, \(\frac{ v ^{2}}{(\omega A )^{2}}+\frac{ x ^{2}}{( A )^{2}}=1\)

So graph between \(v\) and \(x\) is elliptical

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