JEE Mains · Physics · STD 11 - 13. oscillations
When a particle executes simple Harmonic motion, the nature of graph of velocity as function of displacement will be.
- A Circular
- B Ellipitical
- C Sinusoidal
- D Straight line
Answer & Solution
Correct Answer
(B) Ellipitical
Step-by-step Solution
Detailed explanation
For a particle in SHM, its speed depends on position as \(v=\omega \sqrt{A^{2}-x^{2}}\) Where \(\omega\) is angular frequency and \(A\) is amplitude Now \(v ^{2}=\omega^{2} A ^{2}-\omega^{2} x ^{2}\) So, \(\frac{ v ^{2}}{(\omega A )^{2}}+\frac{ x ^{2}}{( A )^{2}}=1\) So graph…
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