JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2022
- Medium
- MCQ
When a particle executes simple Harmonic motion, the nature of graph of velocity as function of displacement will be.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) Ellipitical
Step-by-step Solution
Detailed explanation
For a particle in SHM, its speed depends on position as
\(v=\omega \sqrt{A^{2}-x^{2}}\)
Where \(\omega\) is angular frequency and \(A\) is amplitude Now \(v ^{2}=\omega^{2} A ^{2}-\omega^{2} x ^{2}\)
So, \(\frac{ v ^{2}}{(\omega A )^{2}}+\frac{ x ^{2}}{( A )^{2}}=1\)
So graph between \(v\) and \(x\) is elliptical
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