JEE Mains · Physics · STD 11 - 13. oscillations
Two massless springs with spring constants \(2\,k\) and \(9\,k\), carry \(50\, g\) and \(100 \,g\) masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be
- A \(1: 2\)
- B \(3: 2\)
- C \(3: 1\)
- D \(2: 3\)
Answer & Solution
Correct Answer
(B) \(3: 2\)
Step-by-step Solution
Detailed explanation
\(V _{\max }=\omega A\) \(\Rightarrow \frac{ A _{1}}{ A _{2}}=\frac{\omega_{2}}{\omega_{1}}=\sqrt{\frac{9}{2} \times \frac{1}{2}}=\frac{3}{2}\)
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