JEE Mains · Physics · STD 12 - 3. current electricity
Resistance of the wire is measured as \(2\,\Omega\) and \(3\,\Omega\) at \(10^{\circ}C\) and \(30^{\circ}C\) respectively. Temperature cocoefficient of resistance of the material of the wire is............\(^{\circ}C ^{-1}\)
- A \(0.033\)
- B \(-0.033\)
- C \(0.011\)
- D \(0.055\)
Answer & Solution
Correct Answer
(A) \(0.033\)
Step-by-step Solution
Detailed explanation
\(R = R _{0}(1+\alpha \Delta T )\) \(3= R _{0}(1+\alpha(30-0))\) \(2= R _{0}(1+\alpha(10-0))\) \(\frac{3}{2}=\frac{1+30 \alpha}{1+10 \alpha}\) \(\alpha=\frac{1}{30}=0.033\)
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