JEE Mains · Physics · STD 11 - Vectors
- JEE Mains 2019
- Medium
- Numerical
Two forces \(P\) and \(Q\), of magnitude \(2F\) and \(3F\), respectively, are at an angle \(\theta \) with each other. If the force \(Q\) is doubled, then their resultant also gets doubled. Then, the angle \(\theta \) is ....... \(^o\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(120\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
2\left| {\vec P + \vec Q} \right| = \left| {\vec P + 2\vec Q} \right|\\
\Rightarrow \,13 + 12\,\cos \,\theta = 10 + 6\,\cos \theta \\
\cos = - \frac{1}{2}\\
\theta = {120^ \circ }
\end{array}\)
2\left| {\vec P + \vec Q} \right| = \left| {\vec P + 2\vec Q} \right|\\
\Rightarrow \,13 + 12\,\cos \,\theta = 10 + 6\,\cos \theta \\
\cos = - \frac{1}{2}\\
\theta = {120^ \circ }
\end{array}\)
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