JEE Mains · Physics · STD 12 - 10. Wave optics
Two coherent monochromatic light beams of intensities 4I and 9I are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is xI. The value of \(x\) is ______.
- A 22
- B 24
- C 26
- D 28
Answer & Solution
Correct Answer
(B) 24
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{I}_{\max }=\left(\sqrt{\mathrm{I}_1}+\sqrt{\mathrm{I}_2}\right)^2 \\ & =(\sqrt{4 \mathrm{I}}+\sqrt{9 \mathrm{I}})^2=25 \mathrm{I} \\ & \mathrm{I}_{\min }=\left(\sqrt{\mathrm{I}_1}-\sqrt{\mathrm{I}_2}\right)^2 \\ & =(\sqrt{4 \mathrm{I}}-\sqrt{9…
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