JEE Mains · Physics · STD 11 - 3.2 motion in plane
The ranges and heights for two projectiles projected with the same initial velocity at angles \(42^{\circ}\) and \(48^{\circ}\) with the horizontal are \({R}_{1}, {R}_{2}\) and \({H}_{1}\), \({H}_{2}\) respectively. Choose the correct option:
- A \({R}_{1}>{R}_{2}\) and \({H}_{1}={H}_{2}\)
- B \({R}_{1}={R}_{2}\) and \({H}_{1}<{H}_{2}\)
- C \({R}_{1}<{R}_{2}\) and \({H}_{1}<{H}_{2}\)
- D \({R}_{1}={R}_{2}\) and \({H}_{1}={H}_{2}\)
Answer & Solution
Correct Answer
(B) \({R}_{1}={R}_{2}\) and \({H}_{1}<{H}_{2}\)
Step-by-step Solution
Detailed explanation
Range \({R}=\frac{{u}^{2} \sin 2 \theta}{{g}}\) and same for \(\theta\) and \(90-\theta\) So same for \(42^{\circ}\) and \(48^{\circ}\) Maximum height \({H}=\frac{{u}^{2} \sin ^{2} \theta}{2 {g}}\) \({H}\) is high for higher \(\theta\) So \({H}\) for \(48^{\circ}\) is higher…
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