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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2013
  • Medium
  • MCQ

The earth's magnetic field lines resemble that of a dipole at the centre of the earth. If the magnetic moment of this dipole is close to \(8 \times 10^{22}\, Am^2\), the value of earth 's magnetic field near the equator is close to....\(Gauss\) (radius of the earth \(= 6.4 \times 10^6\, m\))

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Answer & Solution

Correct Answer

(A) \(0.6\)

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Detailed explanation

Gven \(M=8 \times 10^{22}\, \mathrm{Am}^{2}\)

\(\mathrm{d}=\mathrm{R}_{\mathrm{e}}=6.4 \times 10^{6}\, \mathrm{m}\)

Earth's magnetic field, \(\mathrm{B}=\frac{\mu_{0}}{4 \pi} \cdot \frac{2 \mathrm{M}}{\mathrm{d}^{3}}\)

\(=\frac{4 \pi \times 10^{-7}}{4 \pi} \times \frac{2 \times 8 \times 10^{22}}{\left(6.4 \times 10^{6}\right)^{3}}\)

\(\cong 0.6\) \(Gauss\)

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