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JEE Mains · Physics · STD 12 - Magnetism and matter
- JEE Mains 2013
- Medium
- MCQ
The earth's magnetic field lines resemble that of a dipole at the centre of the earth. If the magnetic moment of this dipole is close to \(8 \times 10^{22}\, Am^2\), the value of earth 's magnetic field near the equator is close to....\(Gauss\) (radius of the earth \(= 6.4 \times 10^6\, m\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(0.6\)
Step-by-step Solution
Detailed explanation
Gven \(M=8 \times 10^{22}\, \mathrm{Am}^{2}\)
\(\mathrm{d}=\mathrm{R}_{\mathrm{e}}=6.4 \times 10^{6}\, \mathrm{m}\)
Earth's magnetic field, \(\mathrm{B}=\frac{\mu_{0}}{4 \pi} \cdot \frac{2 \mathrm{M}}{\mathrm{d}^{3}}\)
\(=\frac{4 \pi \times 10^{-7}}{4 \pi} \times \frac{2 \times 8 \times 10^{22}}{\left(6.4 \times 10^{6}\right)^{3}}\)
\(\cong 0.6\) \(Gauss\)
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