JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
Two sources of light emit with a power of \(200 \mathrm{~W}\). The ratio of number of photons of visible light emitted by each source having wavelengths \(300\ \mathrm{nm}\) and \(500 \mathrm{~nm}\) respectively, will be _______.
- A \(1: 5\)
- B \(1: 3\)
- C \(5: 3\)
- D \(3: 5\)
Answer & Solution
Correct Answer
(D) \(3: 5\)
Step-by-step Solution
Detailed explanation
\( \mathrm{n}_1 \times \frac{\mathrm{hc}}{\lambda_1}=200 \) \( \mathrm{n}_2 \times \frac{\mathrm{hc}}{\lambda_2}=200 \) \( \frac{\mathrm{n}_{\mathrm{l}}}{\mathrm{n}_2}=\frac{\lambda_1}{\lambda_2}=\frac{300}{500} \) \( \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{3}{5}\)
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