JEE Mains · Maths · STD 12 - 11. three dimension geometry
For \(a , b \in Z\) and \(| a - b | \leq 10\), let the angle between the plane \(P : ax + y - z = b\) and the line \(l: x -1= a\) \(-y=z+1\) be \(\cos ^{-1}\left(\frac{1}{3}\right)\). If the distance of the point \((6,-6,4)\) from the plane \(P\) is \(3 \sqrt{6}\), then \(a^4+b^2\) is equal to
- A \(25\)
- B \(85\)
- C \(48\)
- D \(32\)
Answer & Solution
Correct Answer
(D) \(32\)
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