ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A pendulum of length \(2 \; m\) consists of a wooden bob of mass \(50 \; g\). A bullet of mass \(75 \; g\) is fired towards the stationary bob with a speed \(v\). The bullet emerges out of the bob with a speed \(\frac{v}{3}\) and the bob just completes the vertical circle. The value of \(v\) is \(\dots \; ms ^{-1}\). (if \(g =10 \; m / s ^{2}\) )

  1. A \(08\)
  2. B \(09\)
  3. C \(10\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(10\)

Step-by-step Solution

Detailed explanation

Considering Only Horizontal direction \((75 v)+0=50(\sqrt{5 g R})+75 \frac{v}{3}\) \(75\left(v-\frac{v}{3}\right)=50 \sqrt{100}\) \(v=10 \; m / s\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app