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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2022
  • Hard
  • Numerical

A pendulum of length \(2 \; m\) consists of a wooden bob of mass \(50 \; g\). A bullet of mass \(75 \; g\) is fired towards the stationary bob with a speed \(v\). The bullet emerges out of the bob with a speed \(\frac{v}{3}\) and the bob just completes the vertical circle. The value of \(v\) is \(\dots \; ms ^{-1}\). (if \(g =10 \; m / s ^{2}\) )

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Answer & Solution

Correct Answer

(C) \(10\)

Step-by-step Solution

Detailed explanation

Considering Only Horizontal direction

\((75 v)+0=50(\sqrt{5 g R})+75 \frac{v}{3}\)

\(75\left(v-\frac{v}{3}\right)=50 \sqrt{100}\)

\(v=10 \; m / s\)

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