JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2019
- Hard
- MCQ
In \(Li^{++},\) electron in first Bohr orbit is excited to a level by a radiation of wavelength \(\lambda .\) When the ion gets deexcited to the ground state in all possible ways(including intermediate emission) a total of six spectral lines are observed. What is the value of \(\lambda \)?.....\(nm\) (Given: \(h = 6.63\times 10^{34}\,js; e = 3 \times 10^8\,ms^{-1}\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(10.8\)
Step-by-step Solution
Detailed explanation
\(\frac{h c}{\lambda}=13.6\, \mathrm{eV}(\mathrm{g})\left\{1-\frac{1}{16}\right\}\)
\(\frac{1240\, \mathrm{eV}}{\lambda}=\frac{15}{16} \times 9 \times 13.6\, \mathrm{eV}\)
\(\lambda=\frac{1240 \times 16}{15 \times 9 \times 13.6}=10.8\, \mathrm{nm}\)
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