JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A galvanometer has a \(50\) \(division\) scale. Battery has no internal resistance. It is found that there is deflection of \(40\) \(divisions\) when \(R = 2400\,\Omega \). Deflection becomes \(20\) \(divisions\) when resistance taken from resistance box is \(4900\,\Omega \) . Then we can conclude

- A Full scale deflection current is \(2\, mA\).
- B Resistance of galvanometer is \(200\,\Omega \,\)
- C Resistance required on \(R.B.\) for a deflection of \(10\) \(divisions\) is \(9800\,\Omega \,\)
- D Current sensitivity of galvanometer is \(20\,\mu A\) \(/ division\)
Answer & Solution
Correct Answer
(D) Current sensitivity of galvanometer is \(20\,\mu A\) \(/ division\)
Step-by-step Solution
Detailed explanation
Let full scale deflection of current \(=1\) In case \(1,\) when \(\mathrm{R}=2400 \Omega\) and deflection of 40 divisions present. \(\therefore \quad \frac{40}{50} \mathrm{I}=\frac{V}{G+R}\) \(\Rightarrow \quad \frac{4}{5} \mathrm{I}=\frac{2}{G+2400}\dots (1)\) In case \(2,\)…
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