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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2021
  • Medium
  • Numerical

The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength \(491\, nm\) is \(0.710\, V\). When the incident wavelength is changed to a new value, the stopping potential is \(1.43\, V\). The new wavelength is ....... \(nm.\)

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Answer & Solution

Correct Answer

(C) \(382\)

Step-by-step Solution

Detailed explanation

\(\frac{ hc }{\lambda}=\phi+ eV _{ s }\)

\(\frac{1240}{491}=\phi+0.71\)

\(\frac{1240}{\lambda}=\phi+1.43 \)

\(\therefore \lambda=382\, nm\)

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