JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the foot of the perpendicular drawn from the point \((1,0,3)\) on a line passing through \((\alpha, 7,1)\) is \(\left(\frac{5}{3}, \frac{7}{3}, \frac{17}{3}\right),\) then \(\alpha\) is equal to
- A \(3.5\)
- B \(4\)
- C \(4.5\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
D.R. of \(\mathrm{BP}=<\frac{5}{3}-\alpha, \frac{7}{3}-7, \frac{17}{3}-1>\) D.R. of \(\mathrm{AP}=<\frac{5}{3}-1, \frac{7}{3}-0, \frac{17}{3}-3>\) \(\mathrm{BP} \perp \mathrm{AP}\) \(\Rightarrow \alpha=4\)
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