JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2023
- Medium
- Numerical
The speed of a swimmer is \(4\,km\,h ^{-1}\) in still water. If the swimmer makes his strokes normal to the flow of river of width \(1\,km\), he reaches a point \(750 \,m\) down the stream on the opposite bank.The speed of the river water is \(.........km h ^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
time to cross the River width \(\omega=1000\,m\)
\(\text { is }=\frac{1\,km }{4\,km / h }\)
Drift \(x = Vm / g \times t\)
Where \(Vm / g\) is velocity of River w.r. to ground.
\(x = Vm / g \times \frac{1}{4}=750\,m =\frac{3}{4}\,km\)
\(Vm / g =3 km / hr\)
Ans is \(3\,km / hr\).
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