JEE Mains · Physics · STD 12 - 3. current electricity
As show in the figure, in steady state, the charge stored in the capacitor is....... \(\times 10^{-6}\,C\).
- A \(10\)
- B \(9\)
- C \(1\)
- D \(100\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
\(q = CV _{100 \Omega}\) \(=\left(1.1 \times 10^{-6}\right)\left(\frac{10}{ R + r } R \right)\) \(=1.1 \times 10^{-6}\left(\frac{10}{110} \times 100\right)\) \(=10\,\mu C\)
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