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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2023
  • Easy
  • Numerical

The root mean square speed of molecules of nitrogen gas at \(27^{\circ} C\) is approximately\(.......m/s\)(Given mass of a nitrogen molecule \(=4.6 \times 10^{-26}\,kg\) and take Boltzmann constant  \(k _{ B }=1.4 \times 10^{-23}\,JK ^{-1}\) )

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Correct Answer

(A) \(523\)

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Detailed explanation

\(V _{ rms }=\sqrt{\frac{3 k _{ B } T }{ m }}=\sqrt{\frac{3 \times 1.4 \times 10^{-23} \times 300}{4.6 \times 10^{-26}}}=523\,m / s\)
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