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JEE Mains · Maths · STD 12 - 6. Application of derivatives

The lengths of the sides of a triangle are \(10+ x ^{2}\), \(10+ x ^{2}\) and \(20-2 x ^{2}\). If for \(x = k\), the area of the triangle is maximum, then \(3 K ^{2}\) is equal to

  1. A \(5\)
  2. B \(10\)
  3. C \(8\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(a =20-2 x ^{2}, b =10+ x ^{2}, c =10+ x ^{2}\) \(=\frac{a+b+c}{2}\) \(=20\) \(\Delta=\sqrt{s(s-a)(s-b)(s-c)}\) \(=\sqrt{20\left(2 x^{2}\right)\left(10-x^{2}\right)\left(10-x^{2}\right)}\) \(=2 \sqrt{10} \sqrt{x^{2}\left(10-x^{2}\right)^{2}}\)…
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