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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2025
  • Easy
  • MCQ

The refractive index of the material of a glass prism is \(\sqrt{3}\). The angle of minimum deviation is equal to the angle of the prism. What is the angle of the prism?

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Answer & Solution

Correct Answer

(A) \(60^{\circ}\)

Step-by-step Solution

Detailed explanation

\(\mu=\frac{\sin \left(\frac{A+\delta_{\min }}{2}\right)}{\sin \frac{A}{2}}\)

Given \(\delta_{\min }=\mathrm{A}\)
\(\begin{aligned}
& \sqrt{3}=\frac{\sin A}{\sin \frac{A}{2}}=\frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}} \\
& \cos \frac{A}{2}=\frac{\sqrt{3}}{2} \\
& A=60^{\circ}
\end{aligned}\)
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