JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2025
- Easy
- MCQ
The refractive index of the material of a glass prism is \(\sqrt{3}\). The angle of minimum deviation is equal to the angle of the prism. What is the angle of the prism?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
\(\mu=\frac{\sin \left(\frac{A+\delta_{\min }}{2}\right)}{\sin \frac{A}{2}}\)
Given \(\delta_{\min }=\mathrm{A}\)
\(\begin{aligned}
& \sqrt{3}=\frac{\sin A}{\sin \frac{A}{2}}=\frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}} \\
& \cos \frac{A}{2}=\frac{\sqrt{3}}{2} \\
& A=60^{\circ}
\end{aligned}\)
Given \(\delta_{\min }=\mathrm{A}\)
\(\begin{aligned}
& \sqrt{3}=\frac{\sin A}{\sin \frac{A}{2}}=\frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}} \\
& \cos \frac{A}{2}=\frac{\sqrt{3}}{2} \\
& A=60^{\circ}
\end{aligned}\)
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