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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2023
  • Easy
  • Numerical

The ratio of de-Broglie wavelength of an \(\alpha\)-particle and a proton accelerated from rest by the same potential is \(\frac{1}{\sqrt{ m }}\), the value of \(m\) is \(........\)

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Answer & Solution

Correct Answer

(C) \(8\)

Step-by-step Solution

Detailed explanation

\(\frac{\lambda_\alpha}{\lambda_{ p }}=\frac{ h }{\frac{\sqrt{2 m _\alpha q _\alpha V }}{ h }}\)

\(\frac{\sqrt{2 m _{ p } q _{ p } V }}{\lambda_{ p }}=\sqrt{\frac{1}{8}}\)

\(m =8\)

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