JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2023
- Easy
- Numerical
The ratio of de-Broglie wavelength of an \(\alpha\)-particle and a proton accelerated from rest by the same potential is \(\frac{1}{\sqrt{ m }}\), the value of \(m\) is \(........\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
\(\frac{\lambda_\alpha}{\lambda_{ p }}=\frac{ h }{\frac{\sqrt{2 m _\alpha q _\alpha V }}{ h }}\)
\(\frac{\sqrt{2 m _{ p } q _{ p } V }}{\lambda_{ p }}=\sqrt{\frac{1}{8}}\)
\(m =8\)
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