JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The ratio of de-Broglie wavelength of an \(\alpha\)-particle and a proton accelerated from rest by the same potential is \(\frac{1}{\sqrt{ m }}\), the value of \(m\) is \(........\)
- A \(4\)
- B \(16\)
- C \(8\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
\(\frac{\lambda_\alpha}{\lambda_{ p }}=\frac{ h }{\frac{\sqrt{2 m _\alpha q _\alpha V }}{ h }}\) \(\frac{\sqrt{2 m _{ p } q _{ p } V }}{\lambda_{ p }}=\sqrt{\frac{1}{8}}\) \(m =8\)
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